Zverev Wins in Four Sets to Reach Wimbledon Round Two
Zverev fired 21 aces and won three tiebreaks to extend his perfect record against Alexander Blockx to 3-0.
- On Tuesday, June 30, 2026, French Open champion Alexander Zverev defeated Belgian debutant Alexander Blockx 6-4, 6-7, 7-6, 7-6 on Centre Court to reach the Wimbledon second round.
- Fresh from capturing his maiden Grand Slam title at the French Open earlier this month, Zverev extended his perfect head-to-head record against Blockx to 3-0 with Tuesday's victory.
- Zverev's serve proved decisive as he fired 21 aces and maintained composure through three tie-breaks against the 21-year-old debutant in a hard-fought contest.
- The second seed advances to face France's Valentin Royer in the next round of the Wimbledon Tennis Championships, continuing his pursuit of back-to-back Grand Slam titles.
- Redemption was at stake for Zverev, who was beaten in round one last year and has never enjoyed a deep run at Wimbledon in nine previous appearances.
19 Articles
19 Articles
Alexander Zverev wins his tricky opening match against Belgian Alexander Blockx in four tight sets – and feels a new freedom as Grand Slam winner.
Alexander Blockx Vs Alexander Zverev Highlights, Wimbledon 2026: Zverev Wins Epic Four-Set Battle To Reach Round Two
Alexander Zverev defeated Alexander Blockx in four sets as it happened on Centre Court, Wimbledon, firing 21 aces to reach the second round. Read the full match report, key moments and highlights
The freshly baked French Open winner Alexander Zverev is having a hard time on the lawn in Wimbledon, but he can defeat the tedious Belgian Alexander Blockx. Overall, however, the German balance is out.
The freshly baked French Open winner will start the next Grand Slam tournament. And Alexander Zverev will complete the Wimbledon opener – in contrast to the previous year.

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